Question

The solubility product of Al(OH)3, is 2.7 x 10! Calculate its solubility in g/l and also find out pH of this solution

Answer 1

It is AB 3 type salt so the value

of ksp=27 s*s*s*s holds good
$fourth \: root \: of \sqrt{ \frac{2.7 }{27} }$
so k=fourth root of 1/10

then pH=Log k -2.303 RT

Then pOH=14-pH

then u get the answee