The solubility product of Fe(OH)3 is 1.1 10-36. What is the solubility of
Fe(OH)3 in moles per litre and grams per litre.
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Answer
Fe(OH)
3
=Fe
3+
+3OH
⊝
∴[Fe
3+
][OH
−
]
3
=K
sp
of Fe(OH)
3
=1×10
−36
⇒[OH
⊝
]
3
=
0.001
1×10
−36
⇒[OH
⊝
]=(10
−33
)
Y
3
=10
−11
M
∴ The minimum concentration of OH
⊝
will be 10
−11
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