Question

The solubility product of ferric hydroxide is 1.1×10^-36 M1.1×10−36M at 25°C. calculate the solubility of ferric hydroxide in gram/litre.gram/litre.​

Answer 1

Answer:

Fe(OH)3​=Fe3++3OH⊝

∴[Fe3+][OH−]3=Ksp​ of Fe(OH)3​=1×10−36

⇒[OH⊝]3=0.0011×10−36​

⇒[OH⊝]=(10−33)Y3​=10−11M

∴ The minimum concentration of OH⊝ will be 10−11M

Answer 2

Answer:

Fe(OH)3=Fe3++3OH⊝

∴[Fe3+][OH−]3=Ksp of Fe(OH)3=1×10−36

⇒[OH⊝]3=0.0011×10−36

⇒[OH⊝]=(10−33)Y3=10−11M

∴ The minimum concentration of OH⊝ will be 10−11M .