The solubility product of Mg(OH)2 is 4X10-12, solubility of Mg(OH)2 is *
a) 4×10 -4 mol L-1
b)1×10-12 mol L-1
c)1×10-4 mol L-1
d)2×10-5 mol L-1
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Ksp of Mg(OH)2 (s) is 4 x 10-12. The number of moles of Mg2+ ions in 1L saturated solution of Mg(OH)2 in 0.1 (M) NaOH solution is (A) 4 x 10-10 (B) 10+ (C) 2 x 10 (D) 8 x 10-6
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I think option D will be your answer..
Hope it will be correct
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