Question

The solubility s of zirconium phosphate is related to its solubility product by the relation

Answer 1

Answer:

$4s^3$

Explanation:

Zirconium Phosphate has the following formula $Zr(HPO_4)_2.nH_2O$.

When It is dissolved in water it dissociates as follows

$Zr(HPO_4)_2.nH_2O$ ⇄ $Zr^{2+} + 2HPO_4^{-}$

                                s                    2s

$K_{sp}= s.(2s)^2 = 4s^3$