The solublity of salt is 60 gm per 100 gm of water. How much salt is required to prepare 40 gm of its saturated solution?
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Answer:
Given:
Mass of the salt= 60g,
Mass of water=100g,
Therefore 60g of salt is soluble in 100g of water.
Therefore 1g of salt is soluble in=100/60g of water. =5/3g of water.
Therefore 40g of salt is soluble in= 40*5/3= 20/3= 6.66g= 6.67g of water.
Explanation
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