Question

The solution contains 40g chloroform and 60 g acetone find the mole fraction of both the components

Answer 1

Hi,

Here is your answer

Given:

Mass of chloroform(CHCl₃)=40g

Mass of acetone(C₃H₆O)=60g

To Find:

Mole fractions of chloroform and acetone

Solution:

Molar mass of CHCl₃=12+1+106.5=119.5

Number of moles of chloroform=Given mass/Molar mass

Number of moles of chloroform=40/119.5=0.33moles

Molar mass of C₃H₆O=36+6+16=58

Number of moles of acetone=60/58=1.03moles

Mole fraction of chloroform=No: of moles of chloroform/No: of moles of solution.

Mole fraction of chloroform=0.33/0.33+1.03=0.24

Mole fraction of acetone=1-0.24=0.76

Notes:

1.Number of moles of a substance=Given mass of that substance/Molar mass

2. Mole fraction of a substance=Number of moles of a substance/ Number of moles in the solution.

Hope this helps you.