The solution for the above question.
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4
Hey!!!....Here is ur answer
let the numbers are 2x, 3x and 4x
then...
(2x)^3+(3x)^3+(4x)^3=33957
8x^3+27x^3+64x^3=33957
x^3 (8+27+64)=33957
x^3=33957/99
x^3=343
x=7
2x=14
3x=21
4x=28
So the numbers are 14 , 21 and 28
Hope it will help you
let the numbers are 2x, 3x and 4x
then...
(2x)^3+(3x)^3+(4x)^3=33957
8x^3+27x^3+64x^3=33957
x^3 (8+27+64)=33957
x^3=33957/99
x^3=343
x=7
2x=14
3x=21
4x=28
So the numbers are 14 , 21 and 28
Hope it will help you
Answered by
1
here is your answer hope it will help you
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