The solution for the pair of equations 1/16x+1/15y=9/20,,,,,,,,,1/20x-1/27y=4/45............
a.1/4,1/3
b.1/3,1/4
c.3,4
d.4,3
plz ans as soon as possible ......I will mark u brainliest if ur ans satisfy me...
yashodha:
u have to shame on u.i give the correct answer but u reported my answer.
if u want answer by using options u should mention in ur question first
Answers
Answered by
70
solution:
Friend i have solved it and answer will come option (D)
So, let's check it.
Here, value of x= 4 and y= 3
Putting it in 1st equation.
=> 1/16*4 + 1/15*3
=> 1/4+ 1/5
=> 9/20= RHS [Hence, it is solution ]
Now, putting it in 2nd equation.
=> 1/20*4 - 1/27*3
=> 1/5 - 1/9
=> 4/45= RHS [Hence, it also solution of 2nd equation]
Btw, you can also solve the equation and gain answer.
____________________
Hope it helps☺
#Amrit⭐
Friend i have solved it and answer will come option (D)
So, let's check it.
Here, value of x= 4 and y= 3
Putting it in 1st equation.
=> 1/16*4 + 1/15*3
=> 1/4+ 1/5
=> 9/20= RHS [Hence, it is solution ]
Now, putting it in 2nd equation.
=> 1/20*4 - 1/27*3
=> 1/5 - 1/9
=> 4/45= RHS [Hence, it also solution of 2nd equation]
Btw, you can also solve the equation and gain answer.
____________________
Hope it helps☺
#Amrit⭐
Answered by
58
Ans. = ( 1/4 , 1/3 )
Step-by-step explanation:
1/16x+1/15y=9/20 .eq 1
1/20x-1/27y=4/45 .eq 2
multiplying eq 1 with 1/5
1/80x + 1/75y=9/100 .eq 3
multiplying eq 2 with 1/4
1/80x - 1/108y=4/180 .eq 4
now subtract eq 4 from eq 3
1/80x +1/75y = 9/100
- (1/80x -1/108y)= 4/180
__________________
1/75y + 1/108y = 9/100 - 4/180
=36+25/2700y = 81-20/900
=61/2700y = 61/900
=> 1/y = 61×2700/900×61
=> 1/y = 3
________
[=> y =1/3 ]
________
putting the value of y in eq 1
1/16x +1/(15×1/3) = 9/20
=>1/16x + 1/5 = 9/20
=>1/16x = 9/20-1/5
=>1/16x = 9-4/20
=>1/16x = 5/20
=>1/x = 5×16/20
=>1/x = 80/20
=>1/x = 4
___________
[=> x =1/4 ]
___________
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