Question

The solution of 13-4cos^2=12sinx is

Answer 1

Answer:sin x = 12/13

cos2x=1−sin2x=1−144169=25/169

→cosx=513sin2x=2sinx.cosx=2(1213)(513)=120/169=071

cos2x=2cos2x−1=−119/169=−0.70