Math, asked by dhruv086, 11 months ago

The solution of 13-4cos^2=12sinx is

Answers

Answered by Martinoforiagyei

0

Answer:sin x = 12/13

cos2x=1−sin2x=1−144169=25/169

→cosx=513sin2x=2sinx.cosx=2(1213)(513)=120/169=071

cos2x=2cos2x−1=−119/169=−0.70

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