Question

The solution of 2x+3y=8,4x+6y=14 is

Answer 1

Hope it is helpful for you..............

Answer 2

no solution

Given equations are

2x+3y =8 ...... 1

4x+6y=14 ...... 2

On comparing the equation 1 with $a_{1}x+ b_{1}y +c_{1} = 0$ we get $a_{1} = 2\\ b_{1} = 3 \\c_{1} = -8$

On comparing the equation 2 with $a_{2}x+ b_{2}y +c_{2} = 0$ we get $a_{2} =4 \\ b_{2} = 6 \\ c_{2} =-14$

$\frac{a_{1} }{a_{2} } = \frac{2}{4} = \frac{1}{2}$

$\frac{b_{1} }{b_{2} } = \frac{3}{6} =\frac{1}{2}$

$\frac{c_{1} }{c_{2} } =\frac{-8}{-14} =\frac{4}{7}$

since $\frac{a_{1} }{a_{2} } = \frac{{b_{1} } }{b_{2} } but not equal to \frac{c_{1} }{c_{2} }$

which means the above two equations are inconsistent and have no solution