the solution of 2x - 5Y = 4 and 3x - 2Y = -16
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Answer:
Step-by-step explanation:
2x-5y = 4 (1)
3x-2y = -16 (2)
Subtracting (2) from (1)
2x-5y-3x+2y = 4+16
-x-3y = 20
-(x+3y) = 20
x+3y = -20
x+3y+20 = 0
shreevivas:
wrong
Answered by
2
here,
2x-5y = 4
2x = 4+5y (equation one)
x = (4+5y)/2 (equation two)
3x-2y = -16
putting the value of x here from equation two
3*(4+5y)/2 - 2y = -16
(12+15y)2 - 2y = -16
(12+15y-4y)/2 = -16
12+15y-4y = -16*2
12+11y = -32
11y = -32-12
11y = -44
y = -44/11
therefore, y = -4
putting this value in equation one we get,
2x-5y = 4
2x-5(-4) = 4
2x+20 = 4
2x = 4-20
2x = -16
x = -16/2
x = -8
therefore,
x = -8
y = -4
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