The solution of 2x + y - 6 = 0 and 3x - y -
4 = 0 is:
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let 2x+y-6=0 be equation 1
let 3x-y-4=0 be equation 2
now,
multiply( 2x+y=6)*3
6x+3y=18 equation3
multiply(3x-y=4)*2
6x-2y=8 equation4
on subtracting equation 3 and 4:-
we get; 6x+3y=18
6x-2y=8
hence, 5y=10
y=2
x=(8+2y)/6=(8+4)/6=12/6=2.
Step-by-step explanation:
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