Question

the solution of 3(x^2-14)=(x+1)^2+(x-2)^2+(x-5)^2 is​

Answer 1

Answer:

-2

Step-by-step explanation:

implifying

3(x + -2) + 2(x + 1) = (-14)

Reorder the terms:

3(-2 + x) + 2(x + 1) = (-14)

(-2 * 3 + x * 3) + 2(x + 1) = (-14)

(-6 + 3x) + 2(x + 1) = (-14)

Reorder the terms:

-6 + 3x + 2(1 + x) = (-14)

-6 + 3x + (1 * 2 + x * 2) = (-14)

-6 + 3x + (2 + 2x) = (-14)

Reorder the terms:

-6 + 2 + 3x + 2x = (-14)

Combine like terms: -6 + 2 = -4

-4 + 3x + 2x = (-14)

Combine like terms: 3x + 2x = 5x

-4 + 5x = (-14)

-4 + 5x = -14

Solving

-4 + 5x = -14

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.

-4 + 4 + 5x = -14 + 4

Combine like terms: -4 + 4 = 0

0 + 5x = -14 + 4

5x = -14 + 4

Combine like terms: -14 + 4 = -10

5x = -10

Divide each side by '5'.

x = -2

Simplifying

x = -2