the solution of 3x^2 +( K - 1) x+ 9 = 0 then k=?
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a=3
b=k-1
c=9
b^2-4ac
(k-1)^2-4(3)(9)
k^2+1-2k-108
k^2-2k-107=0
k(k-2)-107=0
(k-107)(k-2)=0 ..... k-2=0=k=2
k-107=0
k=107
k=107,2
b=k-1
c=9
b^2-4ac
(k-1)^2-4(3)(9)
k^2+1-2k-108
k^2-2k-107=0
k(k-2)-107=0
(k-107)(k-2)=0 ..... k-2=0=k=2
k-107=0
k=107
k=107,2
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