Chemistry, asked by bhagatkaran013, 1 month ago

the solution of 4.5 g of pure non electrolyte in 100g of water was found to freeze at -0.465°C the molecular mass of solute is closest to​

Answers

Answered by abhi178
1

Given info : the solution of 4.5 g of pure non electrolyte in 100g of water was found to freeze at -0.465°C.

To find : the molecular mass of solute is closest to..

solution : given mass of non electrolyte solute is 4.5 g

let molecular mass of solute is M

so, no of moles of solute = 4.5/M

now molality = no of moles of solute/mass of solvent in Kg

= (4.5/M)/(100/1000)

= 45/M

now using formula, ∆Tf = Kf × m

where ∆Tf is change in freezing point, Kf is constant and m is molality

here, ∆Tf = 0.465°C , Kf of water = 1.86 °C kg/mol and m = 45/M

so, 0.465 = 1.86 × 45/M

⇒M = 1.86 × 45/0.465

= 180g

Therefore the molecular mass of solute is 180g

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