Math, asked by karthikguruvu, 7 months ago

The solution of 7X+5y-
132+4=0,9x+2y+112=37,3x-y+z=2 is​

Answers

Answered by pakistanmurdabad202
0

7x+5y-132+4=0

=7x+5y-128=0

=7x+5y=128

So 7x= 128/2 And 5y = 128/2

7x = 64 and 5y = 64

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