Question

the solution of a pair of linear equation x+y=3 and 3x+y=5 is ______​

Answer 1

Kx−2y=3 and 3x+y=5 are intersecting lines

Kx−2y=3 and 3x+y=5 are intersecting lines⇒ form intersecting lines a1x+b1y+c1=0

Kx−2y=3 and 3x+y=5 are intersecting lines⇒ form intersecting lines a1x+b1y+c1=0and a2x+b2y+c2=0

Kx−2y=3 and 3x+y=5 are intersecting lines⇒ form intersecting lines a1x+b1y+c1=0and a2x+b2y+c2=0⇒a2a1=b2b1

Kx−2y=3 and 3x+y=5 are intersecting lines⇒ form intersecting lines a1x+b1y+c1=0and a2x+b2y+c2=0⇒a2a1=b2b1⇒3k=1−2

Kx−2y=3 and 3x+y=5 are intersecting lines⇒ form intersecting lines a1x+b1y+c1=0and a2x+b2y+c2=0⇒a2a1=b2b1⇒3k=1−2∴k=−6

Kx−2y=3 and 3x+y=5 are intersecting lines⇒ form intersecting lines a1x+b1y+c1=0and a2x+b2y+c2=0⇒a2a1=b2b1⇒3k=1−2∴k=−6∴ the value of k is not equal to−6