the solution of an equation 5(X+p)=15 find the value of p
Answers
Answer:
X-3
Step-by-step explanation:
5(X-p)=15
divide both side by 5
X-p=3
add p on both sides
X=3+p
subtract 3 on both sides
p=X-3
Step-by-step explanation:
x + 3 = 0
LHS = x + 3
Put x = 3, we get
LHS = 3 + 3 = 6 ≠ RHS
So, the equation is not satisfied.
(ii) x + 3 = 0
LHS = x + 3
Put x = 0, we get
LHS = 0 + 3 = 3 ≠ RHS
So, the equation is not satisfied.
(iii) x + 3 = 0
LHS = x + 3
Put x = -3, we get
LHS = -3 + 3 = 0 = RHS
So, the equation is satisfied.
(iv) x - 7 = 1
LHS = x - 7
Put x = 7, we get
LHS = 7 - 7 = 0 ≠ RHS
So, the equation is not satisfied.
(v) x - 7 = 1
LHS = x - 7
Put x = 8, we get
LHS = 8 - 7 = 1 = RHS
So, the equation is satisfied.
(vi) 5x = 25
LHS = 5x
Put x = 0, we get
LHS = 5 * 0 = 0 ≠ RHS
So, the equation is not satisfied.
(vii) 5x = 25
LHS = 5x
Put x = 5, we get
LHS = 5 * 5 = 25 = RHS
So, the equation is satisfied.
(viii) 5x = 25
LHS = 5x
Put x = -5, we get
LHS = 5 * (-5) = -25 ≠ RHS
So, the equation is not satisfied.
(ix) m/3 = 2
LHS = m/3
Put m = -6, we get
LHS = -6/3 = -2 ≠ RHS
So, the equation is not satisfied.
(x) m/3 = 2
LHS = m/3
Put m = 0, we get
LHS = 0/3 = 0 ≠ RHS
So, the equation is not satisfied.
(xi) m/3 = 2
LHS = m/3
Put m = 6, we get
LHS = 6/3 = 2 = RHS
So, the equation is satisfied.