the solution of CuSo4 was electrolyted in 1.5 ampier current till 10min. calculate the amount of copper stored on carhode
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first we will calculate Q
Q=IT
=1.5 X600seconds=900
amount of copper stored=MQ/nF
value of F=96500
M=63g
n=2 electrons and Q we calculated above .
putting the values we get amount of copper=0.29g
I'm not that sure about the answer ..but I think it is maybe correct
Q=IT
=1.5 X600seconds=900
amount of copper stored=MQ/nF
value of F=96500
M=63g
n=2 electrons and Q we calculated above .
putting the values we get amount of copper=0.29g
I'm not that sure about the answer ..but I think it is maybe correct
zander07:
oh nice haha thank you
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