the solution of(D2-2D+1)y=X2 is
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(D² − 2D + 1)y = x ²+ 3x + 1.
Answer :
Since the right-hand side is a polynomial of degree 2, the trial solution should be a polynomial of degree 2, say y = Ax² + Bx + C. Now plug this into the left-hand side and solve for the coefficients. The answer is
y = x ² + 7x + 13 + C₁eˣ + C₂xeˣ
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