the solution of f(x)x3-3x2+x+2 is 1, 3, 5
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Step-by-step explanation:
given data
f(x)=x3-3x2+x+2
let x equal to 1 we get
(1)^3-3(1)^2+(1)+2=3
let x equal to 3 we get
(3)^3-3(3)^2+(3)+2 = 5
let x equal to 5 we get
(5)^3-3(5)^2+(5)+2 =7
the solution is ...
3,5,7
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