Question

The solution of given pair of linear equations 2x+y=2and 2y-x=4​

Answer 1

Answer:

Refer to the attachment for your answer..

Answer 2

Answer:

To Find:- Solution of the Equation

Solution:-

Given

2x+y=2 (Eq. 1)

also

2y-x=4

then

$2y = x + 4 \\ y = \frac{x + 4}{2}$

Therefore I can use (x+4)/2 in place of y (Eq. 2)

So putting the value of y from (Eq. 2) to (Eq. 1)

that is

$2x + \frac{x + 4}{2} = 2 \\ \frac{4x}{2} + \frac{x + 4}{2} = 2 \\ \frac{5x + 4}{2} = 2 \\ 5x + 4 = 2 \times 2 = 4 \\ 5x = 4 - 4 = 0 \\ x = \frac{0}{5} \\ x = 0$

Therefore the value of x=0

then value of y from (Eq. 2) is

$y = \frac{x + 4}{2} \\ y = \frac{0 + 4}{2} \\ y = 2$

Let's check whether it's correct or not

2x+y=2

2×0+2=2

2=2

L.H.S=R.H.S

Hence verified

Therefore (0,2) is a solution of the equation.

Hope it helps

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