The solution of Linear congruence 7x ≡1 (mod 11) is?
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so the solution is the volue of x=1/7
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1. 7n ≡ 1 (mod 19)
19 − 2 · 7 = 5
7 − 5 = 2
5 − 2 · 2 = 1
5 − 2 · (7 − 5) = 1
3 · 5 − 2 · 7 = 1
3 · (19 − 2 · 7) − 2 · 7 = 1
3 · 19 − 8 · 7 = 1
−8 · 7 = 1 (mod 19)
11 · 7 = 1 (mod 19)
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