The solution of log3x=1+log 9 is
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log3x - log 9 = 1
We know that:
logx -logy = log(x/y)
log 10 =1
==> log3x -log 9= 1
==> log(3x/9) = log 10
==> 3x/9 = 10
Multiply by 9
==> 3x= 90
Divide by 3:
==> x= 30
To check:
log3(30)-log9 = 1
log90 -log9=1
log(90/9) = 1
log 10 =1
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