The solution of p+q=z
O f(x + y, y+log z)=0
[{x} + y2 +z?. xyz) = 0
Of(xy, y log z) = 0
O f(x-y, y-log z) = 0
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0
Answer:
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Step-by-step explanation:
(x + y, y+log z)=0
[{x} + y2 +z?. xyz) = 0
Of(xy, y log z) = 0
O f(x-y, y-log z) = 0
ANS IS =2
Answered by
0
Answer:
xijzdclhfgknhxkjyfhhlggdljfskjydjkydhjhfghpb
Step-by-step explanation:
jfioggcvvhxmjhflftytsouuyifrgusifrgr
sorry i not know maths
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