Question

The solution of pair of linear equation √2x+√3y=0 and √3x-√2y=0 is *
√3,√2
√6,√6
1,1
0,0​

Answer 1

Answer:

(0,0)

Step-by-step explanation:

Given,

$\sqrt{2} x + \sqrt{3} y = 0 \\ \sqrt{3} x - \sqrt{2} y = 0 \\ \sqrt{2} x + \sqrt{3} y = 0 \\ x = \frac{ \sqrt{6}y }{3} \\ subtitute \: the \: value \: of \: x \\ \sqrt{2} \times \frac{ \sqrt{6}y }{3} + \sqrt{3} y = 0 \\ therefore \: y = 0 \\ \: now \: x = \frac{ \sqrt{6 \times 0} }{3} \\ = x = 0 \\t herefor \: a \: posible \: solution \: is \: (x,y) = (0,0)$

Hope this will help you!