Question

The solution of pair of linear equation in two variable 3 x + 4 y=10 and 2 x- 2 y=2is

Answer 1

EXPLANATION.

• GIVEN

equation are,

3x + 4y = 10 .....(1)

2x - 2y = 2 .......(2)

From equation (1) and (2) we get,

multiply equation (1) by 2

multiply equation (2) by 4

Therefore,

equation will be written as,

6x + 8y = 20 .....(1)

8x - 8y = 8 ......(2)

Therefore,

14x = 28

x = 2

put x = 2 in Equation (1) we get,

6(2) + 8y = 20

12 + 8y = 20

8y = 8

y = 1

Therefore,

value of x = 2 and y = 1

Answer 2

$\bf \huge \fbox \red{ \: answer \: }$

Given:

$\bf \green { \implies \: 3x + 4y = 10}.........(1)$

$\bf \green{ \implies \: 2x - 2y = 2}.......(2)$

equating eq (1) and (2)!!!

★ eq(1) multiply by 2

★eq(2) multiply by 4

$\bf \red{6x + 8y = 20}$

$\bf \underline \red{8x \: - 8y \: = \: \: 8}$

$\bf \pink{14x \: \: \: \: \: = 28}$

$\bf \: x \: \: \: \: = \frac{28}{14}$

$\bf {x \: \: \: \: \: = 2}$

$\bf \underline \blue {x = 2 \: substitute \: \: in \: eq \: (2)}$

$\bf \purple{2x - 2y = 2}$

$\bf \purple{2(2) - 2y = 2}$

$\bf \purple{4 - 2y = 2}$

$\bf \purple{ - 2y = 2 - 4}$

$\bf \purple{ - 2y = - 2}$

$\bf \purple{y = \frac{ - 2}{ - 2} }$

$\bf \orange{y = 1}$

$\bf \fbox { \underline{ \blue {x = 2}}}$

$\bf \fbox{ \underline{ \blue{y = 1}}}$