Math, asked by Rajan6316, 8 months ago

The solution of pair of liner equations x-3y=-8 and x-2y=8 is

Answers

Answered by shubhankaryelve7103
0

Answer:x,y (49,19)

Step-by-step explanation:

x-3y=-8 ...eq 1

x-2y=8 ....eq 2

Subtracting eq 2 from 1

x-3y=-8

- x-2y=8

-y = -19 .:y = 19

taking y = 19 in eq 1

x-3y=-8

x-3×19 =-8

x-57 =-8

x=-8+57

x=49

Answer:x,y (49,19)

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