Question

The solution of pbf2 is 0.46 g/l . What is the solubility product

Answer 1

the solubility product is 23

Answer 2

Answer:$1.0563\times 10^{-7} M^3$is the solubility product.

Explanation:

Strength of the solution = 0.46 g/L

Molar concentration of the $PbF_2=\frac{Strenght}{\text{Molar mass}}$

Molar concentration of the $PbF_2$:

$\frac{0.456}{245.2 g/mol}=0.001876 M$

$PbF_2\rightleftharpoons Pb^{2+}+2F^-$

                   S      2S

$[Pb^+]=0.001876 M$

$[F^-]=2\times 0.001876 M=0.003752 M$

$K_{sp}=S\times 4S^2=0.001876 M\times 4\times (0.003752 M)^2=1.0563\times 10^{-7} M^3$

$1.0563\times 10^{-7} M^3$is the solubility product.