Question

The solution of px+qy=p-q and qx-py=p+q​

Answer 1

Answer:

px+qy=p-q

Multiply this equation with p

${p}^{2} x + pqy = {p}^{2} - pq$

.....equation 1

qx-py=p+q

Multiply this equation with q

${q}^{2} x - pqy = pq + {q}^{2}$

......equation 2

Equation 1+Equation 2

$x( {p}^{2} + {q}^{2} ) = ( {p}^{2} + {q}^{2} )$

x=1

So y=-1

(x,y)=(1,-1)