Question

the solution of set |x-1|<_-1 is
a)(0,2)
b)[0,2]
c)(-infinity,-1] U [1, infinity)
d) phi​

Answer 1

Answer:

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Answer 2

Answer:

(x−2)(x−{x})={x}−1⇒x

2

−2x+1=(x−1){x}

⇒x=1 or x−1={x}⇒x=1 or[x]=1

⇒x∈[1,2)which satisfies given eqution so infinitely many values