Math, asked by mukeshoraon5539, 9 months ago

The solution of (sinx-2)^2 + (cosx-3/2)^2=0

Answers

Answered by reddy75
0

Step-by-step explanation:

(sinx-2)²+(cosx-3÷2)²=0

sin²x+4-4sinx+cos²x+9÷4-3cosx=0

sin²x+cos²x+4+9/4-4sinx-3cosx=0

1+4+9/4-4sinx-3cosx=0

5+9/4-4sinx-3cosx=0

29/4-4sinx-3cosx=0

29/4-4sinx=3cosx

29/12cosx-4/3tanx=0

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