Question

The solution of sulphuric acid contains 80% by weight H2SO4 .specific gravity of this solution is 1.71. Its normality is about ?

Answer 1

Answer : The normality of solution is, 27.918 g/eq

Solution : Given,

Specific gravity = 1.71

% purity = 0.80

Equivalent weight of $H_2SO_4$ = 49 g/eq

Formula used :

$Nomality=\frac{\text{Specific gravity}\times \% purity\times 1000}{\text{equivalent weight of }H_2SO_4}$

Now put all the given values in this formula, we get the normality of solution.

$Nomality=\frac{(1.71g/L)\times (0.80g)\times 1000}{49g/eq}=27.918g/eq$

Therefore, the normality of solution is, 27.918 g/eq