The solution of the 15 < 3(x – 2)/5 < 0 is * 1 point (a) 27 < x < 2 (b) 27 < x < -2 (c) -27 < x < 2 (d) -27 < x < -2
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First, 15<3(x-2)/5
- 15*5/3<x-2
- 25<x-2
- 25+2<x
- 27<x
Now, 3(x-2)/5<0
- x-2<0
- x<2
Answer: 27<x<2
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