The solution of the differential equation (D2 - 4D
+4)y = xe2x sinx is
Select one:
A. (C1 +c2x) e-2x – e2x(xsinx + 2xcosx)
O B. (C1 + c2x)ex - e*(xsinx + 2cosx)
O C. (C1 + c2x) e2x – e2x(xsinx + 2cosx)
D. (C1 ex + c2e2x) - e2x(xsinx + 2cosx)
E. (C1 + c2x) e2x – e2x(xsinx + 2xcosx)
Answers
Answered by
0
(C1 ex + c2e2x) - e2x(xsinx + 2cosx)
Similar questions