The solution of the equation 10t=
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height(H)=120cm
\sf\dashrightarrow \blue{diameter of roller= 84cm}⇢diameterofroller=84cm
\sf\therefore \blue{radius= \dfrac{diameter}{2}}∴radius=
2
diameter
\sf\dashrightarrow \blue{ \dfrac{84}{2}}⇢
2
84
\sf\dashrightarrow \blue{\cancel \dfrac{84}{2}}⇢
2
84
\sf\dashrightarrow \blue{radius= 42cm}⇢radius=42cm
\large\underline\mathfrak{\purple{TO\:FIND,}}
TOFIND,
\sf\dashrightarrow \red{AREA\: OF\:PLAYGROUND }⇢AREAOFPLAYGROUND
FORMULA
\rm{\boxed{\sf{ \circ\:\: C.S.A\: OF\: CYLINDER= 2 \pi rh \:\: \circ}}}
∘C.S.AOFCYLINDER=2πrh∘
\large\underline\mathtt{\purple{SOLUTION,}}
SOLUTion
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