Question

The solution of the equation 2x+3y=2 and x+y=2 is?

Answer 1

Answer:

2x+3y=2 ........(1)

x−2y=8 ........(2)

From (2) we have x=8+2y

Put x=8+2y in (1) we get

2(8+2y)+3y=2

⇒16+4y+3y=2

⇒7y=2−16=−14

⇒y=

2

−14

=−7

Put y=−7 in x=8+2y we get

x=8+2×−7=8−14=−6

∴x=−6 and y=−7

Answer 2

Answer:

2x+3y=2

is a first equation

x+y=2is a second equation

x+y we can multiply with 2

we get 2x+2y=4

subtract second equation from first equation

2x+3y=2

2x+2y=4

(-) (-) (-)

we get y=-2

y=-2 substitute in equation 1 or 2

x+y=2

x-2=2

x=4