Question

The solution of the equation
4 cos2x+6 si?x=5
x=nn
x=nn
x=nn:
none of these​

Answer 1

Answer:

Consider given the trigonometry equation,

4cos

2

x+6sin

2

x=5

4(1−sin

2

x)+6sin

2

x=5

2sin

2

x+4=5

2sin

2

x=1

sin

2

x=

2

1

sinx=

2

1

orsinx=−

2

1

sinx=sin

4

π

orsinx=sin(−

4

π

)

x=

4

π

orx=−

4

π

x=nπ+(−1)

n

4

π

orx=nπ−(−1)

n

4

π

Hence, this is the answer.