Math, asked by soham1331, 2 months ago

The solution of the equation ax + b y + 5 = 0 and bx- a y - 12 0 is (2, -3)
Find the values of a and b.​

Answers

Answered by mudulimanasmini02
1

Answer:

the answer is

a=2, b=3e

Step-by-step explanation:

this figure is helpful to you

Attachments:
Answered by Krishrkpmlakv
2

Answer:

Step-by-step explanation:

Given,

Let ax + by + 5 = 0 equation (1) and bx - ay - 12 = 0 equation ( 2) and also

The point = ( x , y ) = ( 2 , -3 )

Now substituting x,y values in given equations (1) and (2) ,we get

a × 2 + b × (-3) + 5 = 0 and b × 2 - a × (-3) - 12 = 0

2a - 3b + 5 = 0 equation (3) and 2b + 3a - 12 = 0 equation (4)

Now multiply equation (3) by 3 and multiply equation (4) by 2,we get

3 ( 2a - 3b + 5 = 0 ) and 2 ( 2b + 3a - 12 = 0 )

6a - 9b + 15 = 0 and 4b + 6a - 24 = 0

Now subtract above equations ,we get

6a - 9b + 15 - 4b - 6a + 24 = 0

- 13b + 39 = 0

13b = 39

b = 39 / 13

Therefore b = 3

Now substituting b = 3 value in 3rd equation, we get

2a - 3b + 5 = 0

2a - 3 × 3 + 5 = 0

2a - 9 + 5 = 0

2a - 4 = 0

2a = 4

a = 4 / 2

a = 2

Hence a = 2 and b = 3 is the answer.

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