Question

The solution of the equation + b y + 5 = 0 and − − 12 = 0 is

(2, -3)​

Answer 1

Answer:

For a quadratic equation ax2+bx+c = 0, the sum of its roots = –b/a and the product of its roots = c/a

let the roots be 'm' and 'n'

Given one root m = - 4/5

5x^2 + bx + 12 = 0

the sum of its roots = –b/a

m + n = - b/a

-4/5 + n = -b/5

-4 + 5n = -b

5n= -b + 4 -------------1

product of its roots = c/a

m*n = c/a

-4/5 * n = 12/5

-4 n = 12

n = -3 -------------2

Plug-in equation 2 in 1

5(-3) = -b + 4

-15 = -b + 4

b = 4+15

b =19

#Pari Here...❤️

Answer 2

$\huge\red{αηѕωєя}$

For the quadric equation ax2+bx+c = 0, the sum of it's root= -b/a and the product of it's roots = c/a

let the root be 'm' and 'ho

Given one root m = -4/5

5x²+ bx+12= 0

The sum of it's root = - b/a

m+n = -b/5

-4/5+n = -b

5n= -b+4-----------1

product of it's root =c/a

m*n= ca

-4n=12

n= -3----------2

plug in the equation 2 in 1

5(-3) = -b+4

-15= -b+4

b=4+15

b= 19

hope it's help you

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