The solution of the equation(D^2-3D+2)y=0
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How do you evaluate (D²-3D+2) y=0?
Given differential equation is
(D² - 3D + 2)y = 0
Auxiliary equation of above differential equation is
D² - 3D + 2 = 0
=> D² - 2D - D + 2 = 0
=> D(D - 2) - 1(D - 2) = 0
=> (D - 2)(D - 1) = 0
=> D = 2,1
Hence the general solution is given by
y = c₁e²ˣ + c₂eˣ
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