The solution of the equation dydx=x3y2+xy is (A) x2y-2y+1=cye-x22 (B) xy2+2x-y=ce-y2 (C) x2y-2y+x=cxe-y2 (D) none of these
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Answer:
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Explanation:
Given,
dxdy(x2y3+xy)=1
dxdy=x2y3+xy1
dydx=x2y3+xy
dydx−xy=x2y3
x21dydx−xy=y3
substitute x1=u
dydu=−x21dydx
−dydu−uy=y3
dydu+uy=
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