CBSE BOARD XII, asked by nagasai9586, 15 days ago

The solution of the equation dydx=x3y2+xy is (A) x2y-2y+1=cye-x22 (B) xy2+2x-y=ce-y2 (C) x2y-2y+x=cxe-y2 (D) none of these

Answers

Answered by ap0732290
1

Answer:

It's Hard to Fo Sorry I am In 8 Class

Answered by PoisionBabe
0

Explanation:

Given,

dxdy(x2y3+xy)=1

dxdy=x2y3+xy1

dydx=x2y3+xy

dydx−xy=x2y3

x21dydx−xy=y3

substitute x1=u

dydu=−x21dydx

−dydu−uy=y3

dydu+uy=

Similar questions