Question

The solution of the equation (p+2) (P-3) + (p+3) (p-4) = p(2p-5)
b) 7​

Answer 1

Answer:

(p+2)(p-3)+(p+3)(p-4)=p(2p-5)

p×p-3p+2p+p×p-4p+3p-12=2×p×p-5p

2×p×p-2×p×p+3p-18=0

3p-18=0

3p=18

p=18/3

p=6

Answer 2

Answer:

(p+2)(p-3) + (p+3)(p-4) = p(2p-5)

$= > {p}^{2} - p - 6 + {p}^{2} - p - 12 = 2 {p}^{2} - 5p \\ = > 2 {p}^{2} - 2p - 18 = 2 {p}^{2} - 5p \\ = > 3p = 18 \\ = > p = 6$