Question

THE SOLUTION OF THE EQUATION (P+2)(P-3)+(P+3)(P-4)=P(2P-5) IS

Answer 1

(p+2)(p-3)+(p+3)(p-4)=p(2p-5)
p²-3p+2p-6+p²-4p+3p-12=2p²-5p
2p²-2p-18=2p²-5p
-2p+5p=18
3p=18
p=6

Answer 2

$(P+2)(P-3)+(P+3)(P-4)=P(2P-5)\\\\P^2-3P+2P-6+P^2-4P+3P-12=2P^2-5P\\\\2P^2-2P-18=2P^2-5P\ \ \ \ \ |subtract\ 2P^2\ from\ both\ sides\\\\-2P-18=-5P\ \ \ \ \ |add\ 18\ and\ 5P\ to\ both\ sides\\\\3P=18\ \ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{P=6}$