The solution of the equation tan θ + tan 2θ + tan 3 θ = tan θ tan 2 θ tan 3 θ ∀ θϵ (0,π) is given by 1 point (a) π/3 (b) 2π/3 (c) π/6 (d) 5π/6
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(c)π/6
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(c) π/6
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