the solution of the given pair linear equation x+3y = 6and 2x -3y=12 is
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x + 3y = 6 --------(.i )
2x - 3y = 12-------(.ii)
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on add
3x=18
x=6
Substituting the value of x=6 in equation (i),we get
x+3y=6
=6+3y=6
3y=6-6
3y=0
y=0/3
y=0
. .
. x=6 and y=0
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