Question

The solution of the linear equations root2 + root3 = 0 , toot3 − root8 = 0

is​

Answer 1

Step-by-step explanation:

Given,

√2x+√3y=0 .......................(1)

√3x-√8y=0 .......................(2)

From equation (1) we can write,

x=√(3/2)y ..................(3)

substitute the value of (3) in equation (2)

√3x-√8y=0

√3(√(3/2)y)-√8y=0

(3/√2)y-√8y=0

3y–4y = 0

y = 0

Now, substituting y in equation (iii)

We get x=0

Thus, the value of x and y obtained are 0 and 0 respectively.