Question

the solution of the pair of linear equation is x+y=13,x-y=3 find the values of x and y​

Answer 1

$\boxed {\underline {\mathbb {QUESTION:-}}}$

the solution of the pair of linear equation is x+y=13 , x-y=3 find the values of x and y

$\boxed {\underline {\mathbb {FINAL\:ANSWER:-}}}$

$\boxed {x=8}$ and $\boxed {y=5}$

$\boxed {\underline {\mathbb {GIVEN:-}}}$

$\boxed {x+y=13..(1)}$

And

$\boxed{x-y=3..(2)}$

$\boxed {\underline {\mathbb {TO\:FIND:-}}}$

x and y

$\boxed {\underline {\mathbb {THINGS\:TO\:ASSUME:-}}}$

Let x+y=13 as equation 1

And

x-y=3 as equation 2

$\boxed {\underline {\mathbb {METHOD\: USED:-}}}$

Substitution method  

$\boxed {\underline {\mathbb {SOLUTION:-}}}$

So by using $\boxed{x-y=3..(2)}$ let’s create eq3 by caring y to RHS

So 3rd equation will be$\boxed{x=3+y..(3)}$

Now substitute eq3 in eq1 we get-

$x+y=13$

$(3+y)+y=13$ [after putting eq3 in eq1]

$3+y+y=13\\3+2y=13\\2y=13-3\\2y=10\\y=\frac{10}{2}\\\boxed {y=5}$

As we got y value so let’s put it in eq3 to get x  value [Note-you can put value in or from any equation]

We get-

$x=3+y\\x=3+5$

$\boxed {x=8}$

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Answer 2

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