Question

the solution of the pair of linear equation x+y=13 x-y=3​

Answer 1

Step-by-step explanation:

$x + y = 13 \\ x - y = 3 \\ then \\ x = 13 - y \\ then \\ put \: in \: second \: equation \\ 13 - y - y = 0 \\ 13 - 2y = 0 \\ 13 = 2y \\ y = \frac{13}{2} \\ then \\ put \: the \: value \: ofy \: in \: firstequation \\ \\ x + \frac{13}{2} = 13 \\ x = 13 - \frac{13}{2} \\ x = \frac{26 - 13}{2} \\ x = \frac{13}{2}$

Answer 2

Step-by-step explanation:

x + y = 13 \\ x - y = 3 \\ then \\ x = 13 - y \\ then \\ put \: in \: second \: equation \\ 13 - y - y = 0 \\ 13 - 2y = 0 \\ 13 = 2y \\ y = \frac{13}{2} \\ then \\ put \: the \: value \: ofy \: in \: firstequation \\ \\ x + \frac{13}{2} = 13 \\ x = 13 - \frac{13}{2} \\ x = \frac{26 - 13}{2} \\ x = \frac{13}{2}\end{lgathered}$$